Base | Representation |
---|---|
bin | 100000100100001100110011… |
… | …100110100000001101011011 |
3 | 200210010012010021102111120021 |
4 | 200210030303212200031123 |
5 | 122233100041334314011 |
6 | 1224340415425211311 |
7 | 42111450330201343 |
oct | 4044146346401533 |
9 | 623105107374507 |
10 | 143225140151131 |
11 | 416aa49381a825 |
12 | 14091ba9790b37 |
13 | 61bc0c3b2702c |
14 | 27521c30d1d23 |
15 | 118593430d471 |
hex | 8243339a035b |
143225140151131 has 16 divisors (see below), whose sum is σ = 149323774938624. Its totient is φ = 137252407559904.
The previous prime is 143225140151101. The next prime is 143225140151141. The reversal of 143225140151131 is 131151041522341.
It is not a de Polignac number, because 143225140151131 - 215 = 143225140118363 is a prime.
It is a super-2 number, since 2×1432251401511312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143225140151101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 137421880 + ... + 138460186.
It is an arithmetic number, because the mean of its divisors is an integer number (9332735933664).
Almost surely, 2143225140151131 is an apocalyptic number.
143225140151131 is a deficient number, since it is larger than the sum of its proper divisors (6098634787493).
143225140151131 is a wasteful number, since it uses less digits than its factorization.
143225140151131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1098930.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 143225140151131 its reverse (131151041522341), we get a palindrome (274376181673472).
The spelling of 143225140151131 in words is "one hundred forty-three trillion, two hundred twenty-five billion, one hundred forty million, one hundred fifty-one thousand, one hundred thirty-one".
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