143225140151141 has 2 divisors, whose sum is σ = 143225140151142. Its totient is φ = 143225140151140.

The previous prime is 143225140151101. The next prime is 143225140151153. The reversal of 143225140151141 is 141151041522341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103829558123041 + 39395582028100 = 10189679^2 + 6276590^2 .

It is an emirp because it is prime and its reverse (141151041522341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143225140151141 is a prime.

It is a super-3 number, since 3×143225140151141³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143225140151101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71612570075570 + 71612570075571.

It is an arithmetic number, because the mean of its divisors is an integer number (71612570075571).

Almost surely, 2^{143225140151141} is an apocalyptic number.

It is an amenable number.

143225140151141 is a deficient number, since it is larger than the sum of its proper divisors (1).

143225140151141 is an equidigital number, since it uses as much as digits as its factorization.

143225140151141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 35.

Adding to 143225140151141 its reverse (141151041522341), we get a palindrome (284376181673482).

The spelling of 143225140151141 in words is "one hundred forty-three trillion, two hundred twenty-five billion, one hundred forty million, one hundred fifty-one thousand, one hundred forty-one".