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143226229793 is a prime number
BaseRepresentation
bin1000010101100011110…
…0101101010000100001
3111200200200102100000112
42011120330231100201
54321311403323133
6145444111101105
713230164603033
oct2053074552041
9450620370015
10143226229793
1155818522359
1223912211795
13106770b56ca
146d09cc3c53
153ad40a1648
hex2158f2d421

143226229793 has 2 divisors, whose sum is σ = 143226229794. Its totient is φ = 143226229792.

The previous prime is 143226229781. The next prime is 143226229801. The reversal of 143226229793 is 397922622341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134500428049 + 8725801744 = 366743^2 + 93412^2 .

It is an emirp because it is prime and its reverse (397922622341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143226229793 - 28 = 143226229537 is a prime.

It is a super-4 number, since 4×1432262297934 (a number of 46 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (143226829793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71613114896 + 71613114897.

It is an arithmetic number, because the mean of its divisors is an integer number (71613114897).

Almost surely, 2143226229793 is an apocalyptic number.

It is an amenable number.

143226229793 is a deficient number, since it is larger than the sum of its proper divisors (1).

143226229793 is an equidigital number, since it uses as much as digits as its factorization.

143226229793 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1959552, while the sum is 50.

The spelling of 143226229793 in words is "one hundred forty-three billion, two hundred twenty-six million, two hundred twenty-nine thousand, seven hundred ninety-three".