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1432313456681 is a prime number
BaseRepresentation
bin10100110101111100100…
…010001110100000101001
312001221001101110110210202
4110311330202032200221
5141431334221103211
63013555024121545
7205324030334402
oct24657442164051
95057041413722
101432313456681
11502493673598
121b1712a662b5
13a50b3376143
144d477dc69a9
15273cee1753b
hex14d7c88e829

1432313456681 has 2 divisors, whose sum is σ = 1432313456682. Its totient is φ = 1432313456680.

The previous prime is 1432313456647. The next prime is 1432313456779. The reversal of 1432313456681 is 1866543132341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1009532610025 + 422780846656 = 1004755^2 + 650216^2 .

It is an emirp because it is prime and its reverse (1866543132341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1432313456681 - 238 = 1157435549737 is a prime.

It is a super-2 number, since 2×14323134566812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1432313456081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716156728340 + 716156728341.

It is an arithmetic number, because the mean of its divisors is an integer number (716156728341).

Almost surely, 21432313456681 is an apocalyptic number.

It is an amenable number.

1432313456681 is a deficient number, since it is larger than the sum of its proper divisors (1).

1432313456681 is an equidigital number, since it uses as much as digits as its factorization.

1432313456681 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1244160, while the sum is 47.

The spelling of 1432313456681 in words is "one trillion, four hundred thirty-two billion, three hundred thirteen million, four hundred fifty-six thousand, six hundred eighty-one".