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14323211555129 is a prime number
BaseRepresentation
bin1101000001101110000111…
…1011111101000100111001
31212201021201020111011011122
43100123201323331010321
53334132414124231004
650243554220235025
73005550351264341
oct320334173750471
955637636434148
1014323211555129
1146224925768a4
121733b2669ba75
137cb899913659
1437736620bd21
1519c8a6259cbe
hexd06e1efd139

14323211555129 has 2 divisors, whose sum is σ = 14323211555130. Its totient is φ = 14323211555128.

The previous prime is 14323211555101. The next prime is 14323211555161. The reversal of 14323211555129 is 92155511232341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13902659305129 + 420552250000 = 3728627^2 + 648500^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14323211555129 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14323211555129.

It is not a weakly prime, because it can be changed into another prime (14323211455129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161605777564 + 7161605777565.

It is an arithmetic number, because the mean of its divisors is an integer number (7161605777565).

Almost surely, 214323211555129 is an apocalyptic number.

It is an amenable number.

14323211555129 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323211555129 is an equidigital number, since it uses as much as digits as its factorization.

14323211555129 is an evil number, because the sum of its binary digits is even.

The product of its digits is 324000, while the sum is 44.

The spelling of 14323211555129 in words is "fourteen trillion, three hundred twenty-three billion, two hundred eleven million, five hundred fifty-five thousand, one hundred twenty-nine".