14323212043201 has 4 divisors (see below), whose sum is σ = 14323221204052. Its totient is φ = 14323202882352.

The previous prime is 14323212043193. The next prime is 14323212043253. The reversal of 14323212043201 is 10234021232341.

14323212043201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 5438037441600 + 8885174601601 = 2331960^2 + 2980801^2 .

It is a cyclic number.

It is not a de Polignac number, because 14323212043201 - 2³ = 14323212043193 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14323212043201.

It is not an unprimeable number, because it can be changed into a prime (14323212043271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1579986 + ... + 5580571.

It is an arithmetic number, because the mean of its divisors is an integer number (3580805301013).

Almost surely, 2^{14323212043201} is an apocalyptic number.

It is an amenable number.

14323212043201 is a deficient number, since it is larger than the sum of its proper divisors (9160851).

14323212043201 is an equidigital number, since it uses as much as digits as its factorization.

14323212043201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9160850.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 14323212043201 its reverse (10234021232341), we get a palindrome (24557233275542).

The spelling of 14323212043201 in words is "fourteen trillion, three hundred twenty-three billion, two hundred twelve million, forty-three thousand, two hundred one".