Base | Representation |
---|---|
bin | 1101000001110001100011… |
… | …1110101100100111110011 |
3 | 1212201101002121011002020220 |
4 | 3100130120332230213303 |
5 | 3334141312031133133 |
6 | 50244230005304123 |
7 | 3005612263515651 |
oct | 320343076544763 |
9 | 55641077132226 |
10 | 14324135021043 |
11 | 4622916876471 |
12 | 1734143a05043 |
13 | 7cb9b6034ba3 |
14 | 377412b15dd1 |
15 | 19c90c36e5b3 |
hex | d0718fac9f3 |
14324135021043 has 4 divisors (see below), whose sum is σ = 19098846694728. Its totient is φ = 9549423347360.
The previous prime is 14324135021039. The next prime is 14324135021069. The reversal of 14324135021043 is 34012053142341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14324135021043 - 22 = 14324135021039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14324135020995 and 14324135021013.
It is not an unprimeable number, because it can be changed into a prime (14324135021143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2387355836838 + ... + 2387355836843.
It is an arithmetic number, because the mean of its divisors is an integer number (4774711673682).
Almost surely, 214324135021043 is an apocalyptic number.
14324135021043 is a deficient number, since it is larger than the sum of its proper divisors (4774711673685).
14324135021043 is an equidigital number, since it uses as much as digits as its factorization.
14324135021043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4774711673684.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 14324135021043 its reverse (34012053142341), we get a palindrome (48336188163384).
The spelling of 14324135021043 in words is "fourteen trillion, three hundred twenty-four billion, one hundred thirty-five million, twenty-one thousand, forty-three".
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