Base | Representation |
---|---|
bin | 11010101011100101… |
… | …00100110100000001 |
3 | 1100222021112221020102 |
4 | 31111302210310001 |
5 | 213314000120413 |
6 | 10325213452145 |
7 | 1014652613525 |
oct | 152562446401 |
9 | 40867487212 |
10 | 14324223233 |
11 | 6090717a21 |
12 | 29391a1055 |
13 | 147383b448 |
14 | 99c593d85 |
15 | 58c829458 |
hex | 355ca4d01 |
14324223233 has 4 divisors (see below), whose sum is σ = 14525972928. Its totient is φ = 14122473540.
The previous prime is 14324223223. The next prime is 14324223317. The reversal of 14324223233 is 33232242341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33232242341 = 3067 ⋅10835423.
It is a cyclic number.
It is not a de Polignac number, because 14324223233 - 24 = 14324223217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14324223196 and 14324223205.
It is not an unprimeable number, because it can be changed into a prime (14324223223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100874741 + ... + 100874882.
It is an arithmetic number, because the mean of its divisors is an integer number (3631493232).
Almost surely, 214324223233 is an apocalyptic number.
It is an amenable number.
14324223233 is a deficient number, since it is larger than the sum of its proper divisors (201749695).
14324223233 is an equidigital number, since it uses as much as digits as its factorization.
14324223233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 201749694.
The product of its digits is 20736, while the sum is 29.
Adding to 14324223233 its reverse (33232242341), we get a palindrome (47556465574).
The spelling of 14324223233 in words is "fourteen billion, three hundred twenty-four million, two hundred twenty-three thousand, two hundred thirty-three".
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