Base | Representation |
---|---|
bin | 10100110110000011011… |
… | …111001111011000001010 |
3 | 12001221100111222021222211 |
4 | 110312003133033120022 |
5 | 141432104102124224 |
6 | 3014014352335334 |
7 | 205326645035203 |
oct | 24660337173012 |
9 | 5057314867884 |
10 | 1432430114314 |
11 | 502543502161 |
12 | 1b1745b4454a |
13 | a510159c924 |
14 | 4d4896b25aa |
15 | 273da2ac894 |
hex | 14d837cf60a |
1432430114314 has 4 divisors (see below), whose sum is σ = 2148645171474. Its totient is φ = 716215057156.
The previous prime is 1432430114299. The next prime is 1432430114377. The reversal of 1432430114314 is 4134110342341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1381459376025 + 50970738289 = 1175355^2 + 225767^2 .
It is a super-4 number, since 4×14324301143144 (a number of 50 digits) contains 4444 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 358107528577 + ... + 358107528580.
Almost surely, 21432430114314 is an apocalyptic number.
1432430114314 is a deficient number, since it is larger than the sum of its proper divisors (716215057160).
1432430114314 is an equidigital number, since it uses as much as digits as its factorization.
1432430114314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 716215057159.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1432430114314 its reverse (4134110342341), we get a palindrome (5566540456655).
The spelling of 1432430114314 in words is "one trillion, four hundred thirty-two billion, four hundred thirty million, one hundred fourteen thousand, three hundred fourteen".
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