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14325225641 = 105113630091
BaseRepresentation
bin11010101011101100…
…11001100010101001
31100222100102212021122
431111312121202221
5213314224210031
610325251145025
71014664260146
oct152566314251
940870385248
1014325225641
116091242061
1229395a5175
131473acc79c
1499c7753cd
1558c97647b
hex355d998a9

14325225641 has 4 divisors (see below), whose sum is σ = 14338856784. Its totient is φ = 14311594500.

The previous prime is 14325225623. The next prime is 14325225653. The reversal of 14325225641 is 14652252341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14652252341 = 35341507797.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14325225641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14325225601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6813995 + ... + 6816096.

It is an arithmetic number, because the mean of its divisors is an integer number (3584714196).

Almost surely, 214325225641 is an apocalyptic number.

It is an amenable number.

14325225641 is a deficient number, since it is larger than the sum of its proper divisors (13631143).

14325225641 is a wasteful number, since it uses less digits than its factorization.

14325225641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13631142.

The product of its digits is 57600, while the sum is 35.

Adding to 14325225641 its reverse (14652252341), we get a palindrome (28977477982).

The spelling of 14325225641 in words is "fourteen billion, three hundred twenty-five million, two hundred twenty-five thousand, six hundred forty-one".

Divisors: 1 1051 13630091 14325225641