Base | Representation |
---|---|
bin | 1101000001110101111110… |
… | …1110101111100110111001 |
3 | 1212201111011022200221111120 |
4 | 3100131133232233212321 |
5 | 3334201224414140210 |
6 | 50244543451015453 |
7 | 3005653556042061 |
oct | 320353756574671 |
9 | 55644138627446 |
10 | 14325322021305 |
11 | 4623375903319 |
12 | 173441543a589 |
13 | 7cbb44c272c9 |
14 | 3774c66203a1 |
15 | 19c97b68d270 |
hex | d075fbaf9b9 |
14325322021305 has 32 divisors (see below), whose sum is σ = 23032135123200. Its totient is φ = 7603046630400.
The previous prime is 14325322021291. The next prime is 14325322021327. The reversal of 14325322021305 is 50312022352341.
It is not a de Polignac number, because 14325322021305 - 24 = 14325322021289 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 265405 + ... + 5359205.
It is an arithmetic number, because the mean of its divisors is an integer number (719754222600).
Almost surely, 214325322021305 is an apocalyptic number.
14325322021305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14325322021305 is a deficient number, since it is larger than the sum of its proper divisors (8706813101895).
14325322021305 is a wasteful number, since it uses less digits than its factorization.
14325322021305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5094721.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 14325322021305 its reverse (50312022352341), we get a palindrome (64637344373646).
The spelling of 14325322021305 in words is "fourteen trillion, three hundred twenty-five billion, three hundred twenty-two million, twenty-one thousand, three hundred five".
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