Base | Representation |
---|---|
bin | 1000010101101010010… |
… | …0001000000101111001 |
3 | 111200202120102200222011 |
4 | 2011122210020011321 |
5 | 4321340323344122 |
6 | 145450520125521 |
7 | 13230644206066 |
oct | 2053244100571 |
9 | 450676380864 |
10 | 143253340537 |
11 | 5583185a02a |
12 | 2391b3068a1 |
13 | 1067c8b8578 |
14 | 6d0d73dc6d |
15 | 3ad6659377 |
hex | 215a908179 |
143253340537 has 2 divisors, whose sum is σ = 143253340538. Its totient is φ = 143253340536.
The previous prime is 143253340511. The next prime is 143253340613. The reversal of 143253340537 is 735043352341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 133792082176 + 9461258361 = 365776^2 + 97269^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143253340537 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 143253340537.
It is not a weakly prime, because it can be changed into another prime (143253340837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71626670268 + 71626670269.
It is an arithmetic number, because the mean of its divisors is an integer number (71626670269).
Almost surely, 2143253340537 is an apocalyptic number.
It is an amenable number.
143253340537 is a deficient number, since it is larger than the sum of its proper divisors (1).
143253340537 is an equidigital number, since it uses as much as digits as its factorization.
143253340537 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 453600, while the sum is 40.
Adding to 143253340537 its reverse (735043352341), we get a palindrome (878296692878).
The spelling of 143253340537 in words is "one hundred forty-three billion, two hundred fifty-three million, three hundred forty thousand, five hundred thirty-seven".
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