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143253445201 = 306746708003
BaseRepresentation
bin1000010101101010010…
…0100001101001010001
3111200202120122000112121
42011122210201221101
54321340340221301
6145450522254241
713230645123166
oct2053244415121
9450676560477
10143253445201
1155831920729
122391b357381
131067c9240b9
146d0d76a06d
153ad667a3a1
hex215a921a51

143253445201 has 4 divisors (see below), whose sum is σ = 143300156272. Its totient is φ = 143206734132.

The previous prime is 143253445151. The next prime is 143253445207. The reversal of 143253445201 is 102544352341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143253445201 - 27 = 143253445073 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143253445207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23350935 + ... + 23357068.

It is an arithmetic number, because the mean of its divisors is an integer number (35825039068).

Almost surely, 2143253445201 is an apocalyptic number.

It is an amenable number.

143253445201 is a deficient number, since it is larger than the sum of its proper divisors (46711071).

143253445201 is an equidigital number, since it uses as much as digits as its factorization.

143253445201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46711070.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 143253445201 its reverse (102544352341), we get a palindrome (245797797542).

The spelling of 143253445201 in words is "one hundred forty-three billion, two hundred fifty-three million, four hundred forty-five thousand, two hundred one".

Divisors: 1 3067 46708003 143253445201