Base | Representation |
---|---|
bin | 11010101100010001… |
… | …00111110001110111 |
3 | 1100222200102112222020 |
4 | 31112020213301313 |
5 | 213321440040201 |
6 | 10325541404223 |
7 | 1015053004044 |
oct | 152610476167 |
9 | 40880375866 |
10 | 14330002551 |
11 | 6093a05017 |
12 | 293b109673 |
13 | 1474ab2b67 |
14 | 99d25a1cb |
15 | 58d0bba36 |
hex | 356227c77 |
14330002551 has 16 divisors (see below), whose sum is σ = 19769028960. Its totient is φ = 9222272640.
The previous prime is 14330002543. The next prime is 14330002553. The reversal of 14330002551 is 15520003341.
It is not a de Polignac number, because 14330002551 - 23 = 14330002543 is a prime.
It is a super-2 number, since 2×143300025512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14330002553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 652221 + ... + 673833.
It is an arithmetic number, because the mean of its divisors is an integer number (1235564310).
Almost surely, 214330002551 is an apocalyptic number.
14330002551 is a deficient number, since it is larger than the sum of its proper divisors (5439026409).
14330002551 is a wasteful number, since it uses less digits than its factorization.
14330002551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29266.
The product of its (nonzero) digits is 1800, while the sum is 24.
Adding to 14330002551 its reverse (15520003341), we get a palindrome (29850005892).
The spelling of 14330002551 in words is "fourteen billion, three hundred thirty million, two thousand, five hundred fifty-one".
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