143300431403442 has 12 divisors (see below), whose sum is σ = 310484268040830. Its totient is φ = 47766810467808.

The previous prime is 143300431403401. The next prime is 143300431403453. The reversal of 143300431403442 is 244304134003341.

143300431403442 is a `hidden beast` number, since 1 + 4 + 3 + 30 + 0 + 43 + 140 + 3 + 442 = 666.

143300431403442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 138685457637441 + 4614973766001 = 11776479^2 + 2148249^2 .

It is a super-2 number, since 2×143300431403442² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143300431403397 and 143300431403406.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3980567538967 + ... + 3980567539002.

Almost surely, 2^{143300431403442} is an apocalyptic number.

143300431403442 is an abundant number, since it is smaller than the sum of its proper divisors (167183836637388).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143300431403442 is a wasteful number, since it uses less digits than its factorization.

143300431403442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7961135077977 (or 7961135077974 counting only the distinct ones).

The product of its (nonzero) digits is 165888, while the sum is 36.

Adding to 143300431403442 its reverse (244304134003341), we get a palindrome (387604565406783).

The spelling of 143300431403442 in words is "one hundred forty-three trillion, three hundred billion, four hundred thirty-one million, four hundred three thousand, four hundred forty-two".