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14330202434153 = 127112836239639
BaseRepresentation
bin1101000010001000001010…
…1000000010101001101001
31212201221202110001121022222
43100202002220002221221
53334241223310343103
650251112031123425
73006215526625004
oct320420250025151
955657673047288
1014330202434153
11462544a760771
121735357973575
137cc442074b68
1437782a87253b
1519cb64d71638
hexd0882a02a69

14330202434153 has 4 divisors (see below), whose sum is σ = 14443038673920. Its totient is φ = 14217366194388.

The previous prime is 14330202434143. The next prime is 14330202434173. The reversal of 14330202434153 is 35143420203341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14330202434153 - 216 = 14330202368617 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14330202434113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56418119693 + ... + 56418119946.

It is an arithmetic number, because the mean of its divisors is an integer number (3610759668480).

Almost surely, 214330202434153 is an apocalyptic number.

It is an amenable number.

14330202434153 is a deficient number, since it is larger than the sum of its proper divisors (112836239767).

14330202434153 is a wasteful number, since it uses less digits than its factorization.

14330202434153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112836239766.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 14330202434153 its reverse (35143420203341), we get a palindrome (49473622637494).

The spelling of 14330202434153 in words is "fourteen trillion, three hundred thirty billion, two hundred two million, four hundred thirty-four thousand, one hundred fifty-three".

Divisors: 1 127 112836239639 14330202434153