Base | Representation |
---|---|
bin | 1000010101110111110… |
… | …1110011000111111011 |
3 | 111200220112210201122021 |
4 | 2011131331303013323 |
5 | 4321444430331133 |
6 | 145500315135311 |
7 | 13232236214134 |
oct | 2053575630773 |
9 | 450815721567 |
10 | 143310402043 |
11 | 55860a931a6 |
12 | 23936444537 |
13 | 1068b676b83 |
14 | 6d17154c8b |
15 | 3adb67b52d |
hex | 215df731fb |
143310402043 has 2 divisors, whose sum is σ = 143310402044. Its totient is φ = 143310402042.
The previous prime is 143310401987. The next prime is 143310402049. The reversal of 143310402043 is 340204013341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143310402043 - 221 = 143308304891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143310401999 and 143310402017.
It is not a weakly prime, because it can be changed into another prime (143310402049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71655201021 + 71655201022.
It is an arithmetic number, because the mean of its divisors is an integer number (71655201022).
Almost surely, 2143310402043 is an apocalyptic number.
143310402043 is a deficient number, since it is larger than the sum of its proper divisors (1).
143310402043 is an equidigital number, since it uses as much as digits as its factorization.
143310402043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 143310402043 its reverse (340204013341), we get a palindrome (483514415384).
The spelling of 143310402043 in words is "one hundred forty-three billion, three hundred ten million, four hundred two thousand, forty-three".
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