Base | Representation |
---|---|
bin | 1101000010001011110001… |
… | …0111000000010010001110 |
3 | 1212202001020221200012201220 |
4 | 3100202330113000102032 |
5 | 3334300214241442132 |
6 | 50251352111544210 |
7 | 3006251530660560 |
oct | 320427427002216 |
9 | 55661227605656 |
10 | 14331171046542 |
11 | 46258a7496579 |
12 | 173558822b066 |
13 | 7cc56794259c |
14 | 3778bd36d330 |
15 | 19cbbee02a2c |
hex | d08bc5c048e |
14331171046542 has 64 divisors (see below), whose sum is σ = 33547578071040. Its totient is φ = 3995957123424.
The previous prime is 14331171046529. The next prime is 14331171046589. The reversal of 14331171046542 is 24564017113341.
It is a Harshad number since it is a multiple of its sum of digits (42).
It is a junction number, because it is equal to n+sod(n) for n = 14331171046494 and 14331171046503.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1311192 + ... + 5511947.
It is an arithmetic number, because the mean of its divisors is an integer number (524180907360).
Almost surely, 214331171046542 is an apocalyptic number.
14331171046542 is an abundant number, since it is smaller than the sum of its proper divisors (19216407024498).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14331171046542 is a wasteful number, since it uses less digits than its factorization.
14331171046542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6824357.
The product of its (nonzero) digits is 241920, while the sum is 42.
Adding to 14331171046542 its reverse (24564017113341), we get a palindrome (38895188159883).
The spelling of 14331171046542 in words is "fourteen trillion, three hundred thirty-one billion, one hundred seventy-one million, forty-six thousand, five hundred forty-two".
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