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143314212443 = 1187120736489
BaseRepresentation
bin1000010101111000110…
…0010101011001011011
3111200220210222022112012
42011132030111121123
54322001414244233
6145500532540135
713232313464153
oct2053614253133
9450823868465
10143314212443
1155863155a96
122393778164b
131068c3ac34c
146d17867763
153adbb80548
hex215e31565b

143314212443 has 4 divisors (see below), whose sum is σ = 143434950120. Its totient is φ = 143193474768.

The previous prime is 143314212421. The next prime is 143314212469. The reversal of 143314212443 is 344212413341.

143314212443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143314212443 - 224 = 143297435227 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143314212493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60367058 + ... + 60369431.

It is an arithmetic number, because the mean of its divisors is an integer number (35858737530).

Almost surely, 2143314212443 is an apocalyptic number.

143314212443 is a deficient number, since it is larger than the sum of its proper divisors (120737677).

143314212443 is a wasteful number, since it uses less digits than its factorization.

143314212443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120737676.

The product of its digits is 27648, while the sum is 32.

Adding to 143314212443 its reverse (344212413341), we get a palindrome (487526625784).

The spelling of 143314212443 in words is "one hundred forty-three billion, three hundred fourteen million, two hundred twelve thousand, four hundred forty-three".

Divisors: 1 1187 120736489 143314212443