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143314222422113 is a prime number
BaseRepresentation
bin100000100101011111110001…
…010100011001100001100001
3200210102201001120102202010222
4200211133301110121201201
5122241030011420001423
61224445351143332425
742121053014046161
oct4045376124314141
9623381046382128
10143314222422113
11417342473aa486
12140a730b151115
1361c761c786092
14275663417a5a1
151187de9d0a3c8
hex8257f1519861

143314222422113 has 2 divisors, whose sum is σ = 143314222422114. Its totient is φ = 143314222422112.

The previous prime is 143314222422079. The next prime is 143314222422221. The reversal of 143314222422113 is 311224222413341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134128061588689 + 9186160833424 = 11581367^2 + 3030868^2 .

It is a cyclic number.

It is not a de Polignac number, because 143314222422113 - 238 = 143039344515169 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (143314222422913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71657111211056 + 71657111211057.

It is an arithmetic number, because the mean of its divisors is an integer number (71657111211057).

Almost surely, 2143314222422113 is an apocalyptic number.

It is an amenable number.

143314222422113 is a deficient number, since it is larger than the sum of its proper divisors (1).

143314222422113 is an equidigital number, since it uses as much as digits as its factorization.

143314222422113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 55296, while the sum is 35.

Adding to 143314222422113 its reverse (311224222413341), we get a palindrome (454538444835454).

The spelling of 143314222422113 in words is "one hundred forty-three trillion, three hundred fourteen billion, two hundred twenty-two million, four hundred twenty-two thousand, one hundred thirteen".