Base | Representation |
---|---|
bin | 11010101100100001… |
… | …01111111100001011 |
3 | 1100222211102210120121 |
4 | 31112100233330023 |
5 | 213323011230011 |
6 | 10330055204111 |
7 | 1015110056461 |
oct | 152620577413 |
9 | 40884383517 |
10 | 14332133131 |
11 | 609512a828 |
12 | 293b976637 |
13 | 147537a864 |
14 | 99d652831 |
15 | 58d38ce71 |
hex | 35642ff0b |
14332133131 has 2 divisors, whose sum is σ = 14332133132. Its totient is φ = 14332133130.
The previous prime is 14332133117. The next prime is 14332133147. The reversal of 14332133131 is 13133123341.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14332133131 is a prime.
It is a super-2 number, since 2×143321331312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14332133096 and 14332133105.
It is not a weakly prime, because it can be changed into another prime (14332133191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7166066565 + 7166066566.
It is an arithmetic number, because the mean of its divisors is an integer number (7166066566).
Almost surely, 214332133131 is an apocalyptic number.
14332133131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14332133131 is an equidigital number, since it uses as much as digits as its factorization.
14332133131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 25.
Adding to 14332133131 its reverse (13133123341), we get a palindrome (27465256472).
The spelling of 14332133131 in words is "fourteen billion, three hundred thirty-two million, one hundred thirty-three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •