143330414131 has 2 divisors, whose sum is σ = 143330414132. Its totient is φ = 143330414130.

The previous prime is 143330414053. The next prime is 143330414137. The reversal of 143330414131 is 131414033341.

It is a strong prime.

It is an emirp because it is prime and its reverse (131414033341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143330414131 - 2²¹ = 143328316979 is a prime.

It is a super-2 number, since 2×143330414131² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 143330414131.

It is not a weakly prime, because it can be changed into another prime (143330414137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71665207065 + 71665207066.

It is an arithmetic number, because the mean of its divisors is an integer number (71665207066).

Almost surely, 2^143330414131 is an apocalyptic number.

143330414131 is a deficient number, since it is larger than the sum of its proper divisors (1).

143330414131 is an equidigital number, since it uses as much as digits as its factorization.

143330414131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 143330414131 its reverse (131414033341), we get a palindrome (274744447472).

The spelling of 143330414131 in words is "one hundred forty-three billion, three hundred thirty million, four hundred fourteen thousand, one hundred thirty-one".