14333204001113 has 4 divisors (see below), whose sum is σ = 14333212253748. Its totient is φ = 14333195748480.

The previous prime is 14333204001029. The next prime is 14333204001119. The reversal of 14333204001113 is 31110040233341.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 13538845353289 + 794358647824 = 3679517^2 + 891268^2 .

It is a cyclic number.

It is not a de Polignac number, because 14333204001113 - 2¹⁶ = 14333203935577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14333204001119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 398528 + ... + 5368913.

It is an arithmetic number, because the mean of its divisors is an integer number (3583303063437).

Almost surely, 2^{14333204001113} is an apocalyptic number.

It is an amenable number.

14333204001113 is a deficient number, since it is larger than the sum of its proper divisors (8252635).

14333204001113 is an equidigital number, since it uses as much as digits as its factorization.

14333204001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8252634.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 14333204001113 its reverse (31110040233341), we get a palindrome (45443244234454).

The spelling of 14333204001113 in words is "fourteen trillion, three hundred thirty-three billion, two hundred four million, one thousand, one hundred thirteen".