Base | Representation |
---|---|
bin | 1000010101111101000… |
… | …0100101001101011001 |
3 | 111200222001122020202110 |
4 | 2011133100211031121 |
5 | 4322021004244001 |
6 | 145502412222533 |
7 | 13232621526213 |
oct | 2053720451531 |
9 | 450861566673 |
10 | 143332103001 |
11 | 5587226547a |
12 | 2394176aa49 |
13 | 10693004589 |
14 | 6d19da35b3 |
15 | 3add5163d6 |
hex | 215f425359 |
143332103001 has 4 divisors (see below), whose sum is σ = 191109470672. Its totient is φ = 95554735332.
The previous prime is 143332102999. The next prime is 143332103017. The reversal of 143332103001 is 100301233341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100301233341 = 3 ⋅33433744447.
It is not a de Polignac number, because 143332103001 - 21 = 143332102999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143332105001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23888683831 + ... + 23888683836.
It is an arithmetic number, because the mean of its divisors is an integer number (47777367668).
Almost surely, 2143332103001 is an apocalyptic number.
It is an amenable number.
143332103001 is a deficient number, since it is larger than the sum of its proper divisors (47777367671).
143332103001 is an equidigital number, since it uses as much as digits as its factorization.
143332103001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47777367670.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 143332103001 its reverse (100301233341), we get a palindrome (243633336342).
The spelling of 143332103001 in words is "one hundred forty-three billion, three hundred thirty-two million, one hundred three thousand, one".
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