Base | Representation |
---|---|
bin | 11010101100110101… |
… | …00101010100000011 |
3 | 1101000000021202210211 |
4 | 31112122211110003 |
5 | 213324141223133 |
6 | 10330230334551 |
7 | 1015141014322 |
oct | 152632452403 |
9 | 41000252724 |
10 | 14334711043 |
11 | 6096630634 |
12 | 29407ba457 |
13 | 1475a71053 |
14 | 99db240b9 |
15 | 58d6ebbcd |
hex | 3566a5503 |
14334711043 has 4 divisors (see below), whose sum is σ = 14569706368. Its totient is φ = 14099715720.
The previous prime is 14334711029. The next prime is 14334711077. The reversal of 14334711043 is 34011743341.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34011743341 = 31 ⋅1097153011.
It is a cyclic number.
It is not a de Polignac number, because 14334711043 - 229 = 13797840131 is a prime.
It is a super-2 number, since 2×143347110432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14334710996 and 14334711014.
It is not an unprimeable number, because it can be changed into a prime (14334711143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117497571 + ... + 117497692.
It is an arithmetic number, because the mean of its divisors is an integer number (3642426592).
Almost surely, 214334711043 is an apocalyptic number.
14334711043 is a deficient number, since it is larger than the sum of its proper divisors (234995325).
14334711043 is an equidigital number, since it uses as much as digits as its factorization.
14334711043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234995324.
The product of its (nonzero) digits is 12096, while the sum is 31.
The spelling of 14334711043 in words is "fourteen billion, three hundred thirty-four million, seven hundred eleven thousand, forty-three".
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