Base | Representation |
---|---|
bin | 1000010110000001111… |
… | …0100101001101100001 |
3 | 111201000111010002002122 |
4 | 2011200132211031201 |
5 | 4322041223101431 |
6 | 145504422354025 |
7 | 13233260400155 |
oct | 2054036451541 |
9 | 451014102078 |
10 | 143352550241 |
11 | 5588286081a |
12 | 2394858b915 |
13 | 10697313434 |
14 | 6d1c9a7065 |
15 | 3ae0204a7b |
hex | 21607a5361 |
143352550241 has 4 divisors (see below), whose sum is σ = 143353324800. Its totient is φ = 143351775684.
The previous prime is 143352550217. The next prime is 143352550249. The reversal of 143352550241 is 142055253341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143352550241 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (143352550249) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71480 + ... + 540198.
It is an arithmetic number, because the mean of its divisors is an integer number (35838331200).
Almost surely, 2143352550241 is an apocalyptic number.
It is an amenable number.
143352550241 is a deficient number, since it is larger than the sum of its proper divisors (774559).
143352550241 is an equidigital number, since it uses as much as digits as its factorization.
143352550241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 774558.
The product of its (nonzero) digits is 72000, while the sum is 35.
The spelling of 143352550241 in words is "one hundred forty-three billion, three hundred fifty-two million, five hundred fifty thousand, two hundred forty-one".
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