143363330212442 has 4 divisors (see below), whose sum is σ = 215044995318666. Its totient is φ = 71681665106220.

The previous prime is 143363330212411. The next prime is 143363330212481. The reversal of 143363330212442 is 244212033363341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 88018940549281 + 55344389663161 = 9381841^2 + 7439381^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 143363330212442.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35840832553109 + ... + 35840832553112.

Almost surely, 2^{143363330212442} is an apocalyptic number.

143363330212442 is a deficient number, since it is larger than the sum of its proper divisors (71681665106224).

143363330212442 is an equidigital number, since it uses as much as digits as its factorization.

143363330212442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71681665106223.

The product of its (nonzero) digits is 746496, while the sum is 41.

Adding to 143363330212442 its reverse (244212033363341), we get a palindrome (387575363575783).

The spelling of 143363330212442 in words is "one hundred forty-three trillion, three hundred sixty-three billion, three hundred thirty million, two hundred twelve thousand, four hundred forty-two".