Base | Representation |
---|---|
bin | 1101000010101100101101… |
… | …1100101100011110110011 |
3 | 1212202220002020111110021001 |
4 | 3100223023130230132303 |
5 | 3334421322104143443 |
6 | 50255413405542431 |
7 | 3010013626650352 |
oct | 320531334543663 |
9 | 55686066443231 |
10 | 14340014131123 |
11 | 462962515193a |
12 | 1737235874a17 |
13 | 800346a42105 |
14 | 3780bb9b9999 |
15 | 19d03b435d4d |
hex | d0acb72c7b3 |
14340014131123 has 2 divisors, whose sum is σ = 14340014131124. Its totient is φ = 14340014131122.
The previous prime is 14340014131109. The next prime is 14340014131147. The reversal of 14340014131123 is 32113141004341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14340014131123 - 229 = 14339477260211 is a prime.
It is a super-2 number, since 2×143400141311232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14340014131091 and 14340014131100.
It is not a weakly prime, because it can be changed into another prime (14340014131103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170007065561 + 7170007065562.
It is an arithmetic number, because the mean of its divisors is an integer number (7170007065562).
Almost surely, 214340014131123 is an apocalyptic number.
14340014131123 is a deficient number, since it is larger than the sum of its proper divisors (1).
14340014131123 is an equidigital number, since it uses as much as digits as its factorization.
14340014131123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 14340014131123 its reverse (32113141004341), we get a palindrome (46453155135464).
The spelling of 14340014131123 in words is "fourteen trillion, three hundred forty billion, fourteen million, one hundred thirty-one thousand, one hundred twenty-three".
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