Base | Representation |
---|---|
bin | 1101000010101100110110… |
… | …1010100110011111101011 |
3 | 1212202220011211111101222011 |
4 | 3100223031222212133223 |
5 | 3334421411120043201 |
6 | 50255421215140351 |
7 | 3010014561104065 |
oct | 320531552463753 |
9 | 55686154441864 |
10 | 14340051331051 |
11 | 462964414a786 |
12 | 17372462146b7 |
13 | 8003516682c4 |
14 | 3780c2900735 |
15 | 19d03e833151 |
hex | d0acdaa67eb |
14340051331051 has 8 divisors (see below), whose sum is σ = 14503004173440. Its totient is φ = 14177139125952.
The previous prime is 14340051331007. The next prime is 14340051331159. The reversal of 14340051331051 is 15013315004341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14340051331051 - 213 = 14340051322859 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14340051331751) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9449275 + ... + 10861348.
It is an arithmetic number, because the mean of its divisors is an integer number (1812875521680).
Almost surely, 214340051331051 is an apocalyptic number.
14340051331051 is a deficient number, since it is larger than the sum of its proper divisors (162952842389).
14340051331051 is an equidigital number, since it uses as much as digits as its factorization.
14340051331051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20318645.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 14340051331051 its reverse (15013315004341), we get a palindrome (29353366335392).
The spelling of 14340051331051 in words is "fourteen trillion, three hundred forty billion, fifty-one million, three hundred thirty-one thousand, fifty-one".
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