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14340051331051 = 89793320310623
BaseRepresentation
bin1101000010101100110110…
…1010100110011111101011
31212202220011211111101222011
43100223031222212133223
53334421411120043201
650255421215140351
73010014561104065
oct320531552463753
955686154441864
1014340051331051
11462964414a786
1217372462146b7
138003516682c4
143780c2900735
1519d03e833151
hexd0acdaa67eb

14340051331051 has 8 divisors (see below), whose sum is σ = 14503004173440. Its totient is φ = 14177139125952.

The previous prime is 14340051331007. The next prime is 14340051331159. The reversal of 14340051331051 is 15013315004341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14340051331051 - 213 = 14340051322859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14340051331751) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9449275 + ... + 10861348.

It is an arithmetic number, because the mean of its divisors is an integer number (1812875521680).

Almost surely, 214340051331051 is an apocalyptic number.

14340051331051 is a deficient number, since it is larger than the sum of its proper divisors (162952842389).

14340051331051 is an equidigital number, since it uses as much as digits as its factorization.

14340051331051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20318645.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 14340051331051 its reverse (15013315004341), we get a palindrome (29353366335392).

The spelling of 14340051331051 in words is "fourteen trillion, three hundred forty billion, fifty-one million, three hundred thirty-one thousand, fifty-one".

Divisors: 1 89 7933 706037 20310623 1807645447 161124172259 14340051331051