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14340114414011 = 56572534932723
BaseRepresentation
bin1101000010101101000101…
…1011001111100110111011
31212202220100020012100112002
43100223101123033212323
53334422023242222021
650255431351211215
73010016255231321
oct320532133174673
955686306170462
1014340114414011
114629676816961
121737263376b0b
138003617545b9
143780cb041d11
1519d04514450b
hexd0ad16cf9bb

14340114414011 has 4 divisors (see below), whose sum is σ = 14342649352392. Its totient is φ = 14337579475632.

The previous prime is 14340114414007. The next prime is 14340114414013. The reversal of 14340114414011 is 11041441104341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14340114414011 - 22 = 14340114414007 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14340114414013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1267460705 + ... + 1267472018.

It is an arithmetic number, because the mean of its divisors is an integer number (3585662338098).

Almost surely, 214340114414011 is an apocalyptic number.

14340114414011 is a deficient number, since it is larger than the sum of its proper divisors (2534938381).

14340114414011 is an equidigital number, since it uses as much as digits as its factorization.

14340114414011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2534938380.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 14340114414011 its reverse (11041441104341), we get a palindrome (25381555518352).

The spelling of 14340114414011 in words is "fourteen trillion, three hundred forty billion, one hundred fourteen million, four hundred fourteen thousand, eleven".

Divisors: 1 5657 2534932723 14340114414011