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1434012433 = 7414996559
BaseRepresentation
bin101010101111001…
…0100101100010001
310200221100101020121
41111132110230101
510414101344213
6354143510241
750351622160
oct12536245421
93627311217
101434012433
1167650a847
123402b8381
1319b129b89
14d86473d7
1585d6288d
hex55794b11

1434012433 has 8 divisors (see below), whose sum is σ = 1678844160. Its totient is φ = 1199173920.

The previous prime is 1434012413. The next prime is 1434012439. The reversal of 1434012433 is 3342104341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1434012433 - 213 = 1434004241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1434012398 and 1434012407.

It is not an unprimeable number, because it can be changed into a prime (1434012439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2497993 + ... + 2498566.

It is an arithmetic number, because the mean of its divisors is an integer number (209855520).

Almost surely, 21434012433 is an apocalyptic number.

It is an amenable number.

1434012433 is a deficient number, since it is larger than the sum of its proper divisors (244831727).

1434012433 is an equidigital number, since it uses as much as digits as its factorization.

1434012433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4996607.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 1434012433 is about 37868.3566186863. The cubic root of 1434012433 is about 1127.6759169174.

Adding to 1434012433 its reverse (3342104341), we get a palindrome (4776116774).

The spelling of 1434012433 in words is "one billion, four hundred thirty-four million, twelve thousand, four hundred thirty-three".

Divisors: 1 7 41 287 4996559 34975913 204858919 1434012433