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143411000347 is a prime number
BaseRepresentation
bin1000010110001111110…
…1100011010000011011
3111201011120002122120101
42011203331203100123
54322201204002342
6145514311240231
713234600250506
oct2054375432033
9451146078511
10143411000347
115590285319a
1223964079077
13106a6469ab4
146d2666013d
153ae53ed3b7
hex2163f6341b

143411000347 has 2 divisors, whose sum is σ = 143411000348. Its totient is φ = 143411000346.

The previous prime is 143411000333. The next prime is 143411000377. The reversal of 143411000347 is 743000114341.

143411000347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (743000114341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143411000347 is a prime.

It is not a weakly prime, because it can be changed into another prime (143411000377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71705500173 + 71705500174.

It is an arithmetic number, because the mean of its divisors is an integer number (71705500174).

Almost surely, 2143411000347 is an apocalyptic number.

143411000347 is a deficient number, since it is larger than the sum of its proper divisors (1).

143411000347 is an equidigital number, since it uses as much as digits as its factorization.

143411000347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 143411000347 its reverse (743000114341), we get a palindrome (886411114688).

The spelling of 143411000347 in words is "one hundred forty-three billion, four hundred eleven million, three hundred forty-seven", and thus it is an aban number.