Base | Representation |
---|---|
bin | 1000010110001111110… |
… | …1100011010001111011 |
3 | 111201011120002122200221 |
4 | 2011203331203101323 |
5 | 4322201204003233 |
6 | 145514311240511 |
7 | 13234600251004 |
oct | 2054375432173 |
9 | 451146078627 |
10 | 143411000443 |
11 | 55902853277 |
12 | 23964079137 |
13 | 106a6469b59 |
14 | 6d266601ab |
15 | 3ae53ed42d |
hex | 2163f6347b |
143411000443 has 2 divisors, whose sum is σ = 143411000444. Its totient is φ = 143411000442.
The previous prime is 143411000399. The next prime is 143411000461. The reversal of 143411000443 is 344000114341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143411000443 - 29 = 143410999931 is a prime.
It is not a weakly prime, because it can be changed into another prime (141411000443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71705500221 + 71705500222.
It is an arithmetic number, because the mean of its divisors is an integer number (71705500222).
Almost surely, 2143411000443 is an apocalyptic number.
143411000443 is a deficient number, since it is larger than the sum of its proper divisors (1).
143411000443 is an equidigital number, since it uses as much as digits as its factorization.
143411000443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 143411000443 its reverse (344000114341), we get a palindrome (487411114784).
The spelling of 143411000443 in words is "one hundred forty-three billion, four hundred eleven million, four hundred forty-three", and thus it is an aban number.
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