Base | Representation |
---|---|
bin | 100000100110111010000001… |
… | …000000101001010010001001 |
3 | 200210202222011200220212001022 |
4 | 200212322001000221102021 |
5 | 122244121434321142101 |
6 | 1225002054331202225 |
7 | 42131053206455651 |
oct | 4046720100512211 |
9 | 623688150825038 |
10 | 143411122443401 |
11 | 417713519986aa |
12 | 141020528a6375 |
13 | 62037c2c77397 |
14 | 275b1c760b361 |
15 | 118a6bbd02a1b |
hex | 826e81029489 |
143411122443401 has 2 divisors, whose sum is σ = 143411122443402. Its totient is φ = 143411122443400.
The previous prime is 143411122443353. The next prime is 143411122443467. The reversal of 143411122443401 is 104344221114341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 142482992517376 + 928129926025 = 11936624^2 + 963395^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143411122443401 is a prime.
It is not a weakly prime, because it can be changed into another prime (143411122443101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71705561221700 + 71705561221701.
It is an arithmetic number, because the mean of its divisors is an integer number (71705561221701).
Almost surely, 2143411122443401 is an apocalyptic number.
It is an amenable number.
143411122443401 is a deficient number, since it is larger than the sum of its proper divisors (1).
143411122443401 is an equidigital number, since it uses as much as digits as its factorization.
143411122443401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 143411122443401 its reverse (104344221114341), we get a palindrome (247755343557742).
The spelling of 143411122443401 in words is "one hundred forty-three trillion, four hundred eleven billion, one hundred twenty-two million, four hundred forty-three thousand, four hundred one".
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