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143411122443401 is a prime number
BaseRepresentation
bin100000100110111010000001…
…000000101001010010001001
3200210202222011200220212001022
4200212322001000221102021
5122244121434321142101
61225002054331202225
742131053206455651
oct4046720100512211
9623688150825038
10143411122443401
11417713519986aa
12141020528a6375
1362037c2c77397
14275b1c760b361
15118a6bbd02a1b
hex826e81029489

143411122443401 has 2 divisors, whose sum is σ = 143411122443402. Its totient is φ = 143411122443400.

The previous prime is 143411122443353. The next prime is 143411122443467. The reversal of 143411122443401 is 104344221114341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 142482992517376 + 928129926025 = 11936624^2 + 963395^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143411122443401 is a prime.

It is not a weakly prime, because it can be changed into another prime (143411122443101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71705561221700 + 71705561221701.

It is an arithmetic number, because the mean of its divisors is an integer number (71705561221701).

Almost surely, 2143411122443401 is an apocalyptic number.

It is an amenable number.

143411122443401 is a deficient number, since it is larger than the sum of its proper divisors (1).

143411122443401 is an equidigital number, since it uses as much as digits as its factorization.

143411122443401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36864, while the sum is 35.

Adding to 143411122443401 its reverse (104344221114341), we get a palindrome (247755343557742).

The spelling of 143411122443401 in words is "one hundred forty-three trillion, four hundred eleven billion, one hundred twenty-two million, four hundred forty-three thousand, four hundred one".