Base | Representation |
---|---|
bin | 1101000010110001001000… |
… | …1001010000111101100001 |
3 | 1212210000010220100000022202 |
4 | 3100230102021100331201 |
5 | 3334431234224020001 |
6 | 50300131215542545 |
7 | 3010055211356414 |
oct | 320542211207541 |
9 | 55700126300282 |
10 | 14341200220001 |
11 | 462a083716a86 |
12 | 1737506b2aa55 |
13 | 8004a56a5755 |
14 | 378191327b7b |
15 | 19d0aa62496b |
hex | d0b12250f61 |
14341200220001 has 4 divisors (see below), whose sum is σ = 15096000231600. Its totient is φ = 13586400208404.
The previous prime is 14341200219949. The next prime is 14341200220013. The reversal of 14341200220001 is 10002200214341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14341200220001 - 222 = 14341196025697 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14341200220091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 377400005771 + ... + 377400005808.
It is an arithmetic number, because the mean of its divisors is an integer number (3774000057900).
Almost surely, 214341200220001 is an apocalyptic number.
It is an amenable number.
14341200220001 is a deficient number, since it is larger than the sum of its proper divisors (754800011599).
14341200220001 is an equidigital number, since it uses as much as digits as its factorization.
14341200220001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 754800011598.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 14341200220001 its reverse (10002200214341), we get a palindrome (24343400434342).
The spelling of 14341200220001 in words is "fourteen trillion, three hundred forty-one billion, two hundred million, two hundred twenty thousand, one".
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