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14341222433 = 411512316463
BaseRepresentation
bin11010101101100110…
…11011000000100001
31101000110112120202102
431112303123000201
5213332323104213
610331022100145
71015250244056
oct152663330041
941013476672
1014341222433
11609a27874a
122942a1a655
131477210a45
149a093b02d
1558e086158
hex356cdb021

14341222433 has 8 divisors (see below), whose sum is σ = 14788306176. Its totient is φ = 13898772000.

The previous prime is 14341222421. The next prime is 14341222481. The reversal of 14341222433 is 33422214341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14341222433 - 212 = 14341218337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14341222396 and 14341222405.

It is not an unprimeable number, because it can be changed into a prime (14341222033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1152041 + ... + 1164422.

It is an arithmetic number, because the mean of its divisors is an integer number (1848538272).

Almost surely, 214341222433 is an apocalyptic number.

It is an amenable number.

14341222433 is a deficient number, since it is larger than the sum of its proper divisors (447083743).

14341222433 is a wasteful number, since it uses less digits than its factorization.

14341222433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2316655.

The product of its digits is 13824, while the sum is 29.

Adding to 14341222433 its reverse (33422214341), we get a palindrome (47763436774).

The spelling of 14341222433 in words is "fourteen billion, three hundred forty-one million, two hundred twenty-two thousand, four hundred thirty-three".

Divisors: 1 41 151 6191 2316463 94974983 349785913 14341222433