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14341225433 is a prime number
BaseRepresentation
bin11010101101100110…
…11011101111011001
31101000110112201212112
431112303123233121
5213332323203213
610331022122105
71015250255603
oct152663335731
941013481775
1014341225433
11609a27aa27
122942a20335
131477212212
149a093c173
1558e086ea8
hex356cdbbd9

14341225433 has 2 divisors, whose sum is σ = 14341225434. Its totient is φ = 14341225432.

The previous prime is 14341225411. The next prime is 14341225501. The reversal of 14341225433 is 33452214341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14340541504 + 683929 = 119752^2 + 827^2 .

It is a cyclic number.

It is not a de Polignac number, because 14341225433 - 210 = 14341224409 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14341225433.

It is not a weakly prime, because it can be changed into another prime (14341225133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170612716 + 7170612717.

It is an arithmetic number, because the mean of its divisors is an integer number (7170612717).

Almost surely, 214341225433 is an apocalyptic number.

It is an amenable number.

14341225433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341225433 is an equidigital number, since it uses as much as digits as its factorization.

14341225433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 32.

Adding to 14341225433 its reverse (33452214341), we get a palindrome (47793439774).

The spelling of 14341225433 in words is "fourteen billion, three hundred forty-one million, two hundred twenty-five thousand, four hundred thirty-three".