Base | Representation |
---|---|
bin | 10100110111101000011… |
… | …011000100100101000001 |
3 | 12002002201112102020022211 |
4 | 110313220123010211001 |
5 | 141444041110122241 |
6 | 3014454404102121 |
7 | 205416626535022 |
oct | 24675033044501 |
9 | 5062645366284 |
10 | 1434123520321 |
11 | 503232381158 |
12 | 1b1b39094941 |
13 | a531137aa0b |
14 | 4d5aa55cc49 |
15 | 27488cac781 |
hex | 14de86c4941 |
1434123520321 has 2 divisors, whose sum is σ = 1434123520322. Its totient is φ = 1434123520320.
The previous prime is 1434123520279. The next prime is 1434123520337. The reversal of 1434123520321 is 1230253214341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1410783319696 + 23340200625 = 1187764^2 + 152775^2 .
It is a cyclic number.
It is not a de Polignac number, because 1434123520321 - 227 = 1433989302593 is a prime.
It is not a weakly prime, because it can be changed into another prime (1434123520021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717061760160 + 717061760161.
It is an arithmetic number, because the mean of its divisors is an integer number (717061760161).
Almost surely, 21434123520321 is an apocalyptic number.
It is an amenable number.
1434123520321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434123520321 is an equidigital number, since it uses as much as digits as its factorization.
1434123520321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1434123520321 its reverse (1230253214341), we get a palindrome (2664376734662).
The spelling of 1434123520321 in words is "one trillion, four hundred thirty-four billion, one hundred twenty-three million, five hundred twenty thousand, three hundred twenty-one".
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