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14342041011 = 34780680337
BaseRepresentation
bin11010101101101101…
…00010110110110011
31101000112002011122010
431112312202312303
5213333030303021
610331051414003
71015260223434
oct152666426663
941015064563
1014342041011
11609a787761
122943154303
1314774394cc
149a0ab148b
1558e198976
hex356da2db3

14342041011 has 4 divisors (see below), whose sum is σ = 19122721352. Its totient is φ = 9561360672.

The previous prime is 14342041009. The next prime is 14342041013. The reversal of 14342041011 is 11014024341.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (14342041009) and next prime (14342041013).

It is not a de Polignac number, because 14342041011 - 21 = 14342041009 is a prime.

It is a super-2 number, since 2×143420410112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14342041013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2390340166 + ... + 2390340171.

It is an arithmetic number, because the mean of its divisors is an integer number (4780680338).

Almost surely, 214342041011 is an apocalyptic number.

14342041011 is a deficient number, since it is larger than the sum of its proper divisors (4780680341).

14342041011 is an equidigital number, since it uses as much as digits as its factorization.

14342041011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4780680340.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14342041011 its reverse (11014024341), we get a palindrome (25356065352).

The spelling of 14342041011 in words is "fourteen billion, three hundred forty-two million, forty-one thousand, eleven".

Divisors: 1 3 4780680337 14342041011