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143431241334 = 2356342460403
BaseRepresentation
bin1000010110010100101…
…0110000111001110110
3111201012222011222222120
42011211022300321312
54322221344210314
6145520313140410
713235234302233
oct2054512607166
9451188158876
10143431241334
1155913218587
122396a9ba706
13106aa705b04
146d2920c78a
153ae709a8a9
hex21652b0e76

143431241334 has 16 divisors (see below), whose sum is σ = 287372014272. Its totient is φ = 47725491848.

The previous prime is 143431241323. The next prime is 143431241383. The reversal of 143431241334 is 433142134341.

It is a super-2 number, since 2×1434312413342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143431241295 and 143431241304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21226824 + ... + 21233579.

It is an arithmetic number, because the mean of its divisors is an integer number (17960750892).

Almost surely, 2143431241334 is an apocalyptic number.

143431241334 is an abundant number, since it is smaller than the sum of its proper divisors (143940772938).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143431241334 is a wasteful number, since it uses less digits than its factorization.

143431241334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42460971.

The product of its digits is 41472, while the sum is 33.

Adding to 143431241334 its reverse (433142134341), we get a palindrome (576573375675).

The spelling of 143431241334 in words is "one hundred forty-three billion, four hundred thirty-one million, two hundred forty-one thousand, three hundred thirty-four".

Divisors: 1 2 3 6 563 1126 1689 3378 42460403 84920806 127381209 254762418 23905206889 47810413778 71715620667 143431241334