Base | Representation |
---|---|
bin | 1101000010111000010111… |
… | …0001110010010011001001 |
3 | 1212210012011002210022222022 |
4 | 3100232011301302103021 |
5 | 3334444222344102103 |
6 | 50301051520534225 |
7 | 3010154246203361 |
oct | 320560561622311 |
9 | 55705132708868 |
10 | 14343140222153 |
11 | 462a989804346 |
12 | 1737968781375 |
13 | 8007245a3b12 |
14 | 3782d6c459a1 |
15 | 19d170ad5138 |
hex | d0b85c724c9 |
14343140222153 has 2 divisors, whose sum is σ = 14343140222154. Its totient is φ = 14343140222152.
The previous prime is 14343140222083. The next prime is 14343140222171. The reversal of 14343140222153 is 35122204134341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12823475056144 + 1519665166009 = 3580988^2 + 1232747^2 .
It is a cyclic number.
It is not a de Polignac number, because 14343140222153 - 214 = 14343140205769 is a prime.
It is not a weakly prime, because it can be changed into another prime (14343140225153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171570111076 + 7171570111077.
It is an arithmetic number, because the mean of its divisors is an integer number (7171570111077).
Almost surely, 214343140222153 is an apocalyptic number.
It is an amenable number.
14343140222153 is a deficient number, since it is larger than the sum of its proper divisors (1).
14343140222153 is an equidigital number, since it uses as much as digits as its factorization.
14343140222153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 14343140222153 its reverse (35122204134341), we get a palindrome (49465344356494).
The spelling of 14343140222153 in words is "fourteen trillion, three hundred forty-three billion, one hundred forty million, two hundred twenty-two thousand, one hundred fifty-three".
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