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14343140222153 is a prime number
BaseRepresentation
bin1101000010111000010111…
…0001110010010011001001
31212210012011002210022222022
43100232011301302103021
53334444222344102103
650301051520534225
73010154246203361
oct320560561622311
955705132708868
1014343140222153
11462a989804346
121737968781375
138007245a3b12
143782d6c459a1
1519d170ad5138
hexd0b85c724c9

14343140222153 has 2 divisors, whose sum is σ = 14343140222154. Its totient is φ = 14343140222152.

The previous prime is 14343140222083. The next prime is 14343140222171. The reversal of 14343140222153 is 35122204134341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12823475056144 + 1519665166009 = 3580988^2 + 1232747^2 .

It is a cyclic number.

It is not a de Polignac number, because 14343140222153 - 214 = 14343140205769 is a prime.

It is not a weakly prime, because it can be changed into another prime (14343140225153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171570111076 + 7171570111077.

It is an arithmetic number, because the mean of its divisors is an integer number (7171570111077).

Almost surely, 214343140222153 is an apocalyptic number.

It is an amenable number.

14343140222153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14343140222153 is an equidigital number, since it uses as much as digits as its factorization.

14343140222153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 14343140222153 its reverse (35122204134341), we get a palindrome (49465344356494).

The spelling of 14343140222153 in words is "fourteen trillion, three hundred forty-three billion, one hundred forty million, two hundred twenty-two thousand, one hundred fifty-three".