Base | Representation |
---|---|
bin | 1101000010111000010111… |
… | …0001110101011011111001 |
3 | 1212210012011002210222121011 |
4 | 3100232011301311123321 |
5 | 3334444222400010001 |
6 | 50301051521113521 |
7 | 3010154246256004 |
oct | 320560561653371 |
9 | 55705132728534 |
10 | 14343140235001 |
11 | 462a989812a66 |
12 | 17379687888a1 |
13 | 8007245a9916 |
14 | 3782d6c4a53b |
15 | 19d170ad8d51 |
hex | d0b85c756f9 |
14343140235001 has 4 divisors (see below), whose sum is σ = 14343200226432. Its totient is φ = 14343080243572.
The previous prime is 14343140234999. The next prime is 14343140235013. The reversal of 14343140235001 is 10053204134341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14343140235001 - 21 = 14343140234999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14343140235701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29635645 + ... + 30115738.
It is an arithmetic number, because the mean of its divisors is an integer number (3585800056608).
Almost surely, 214343140235001 is an apocalyptic number.
It is an amenable number.
14343140235001 is a deficient number, since it is larger than the sum of its proper divisors (59991431).
14343140235001 is an equidigital number, since it uses as much as digits as its factorization.
14343140235001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59991430.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 14343140235001 its reverse (10053204134341), we get a palindrome (24396344369342).
The spelling of 14343140235001 in words is "fourteen trillion, three hundred forty-three billion, one hundred forty million, two hundred thirty-five thousand, one".
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