14343204013241 has 4 divisors (see below), whose sum is σ = 14345312384592. Its totient is φ = 14341095641892.

The previous prime is 14343204013181. The next prime is 14343204013283. The reversal of 14343204013241 is 14231040234341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14343204013241 - 2²⁶ = 14343136904377 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14343204013198 and 14343204013207.

It is not an unprimeable number, because it can be changed into a prime (14343204015241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1054175471 + ... + 1054189076.

It is an arithmetic number, because the mean of its divisors is an integer number (3586328096148).

Almost surely, 2^{14343204013241} is an apocalyptic number.

It is an amenable number.

14343204013241 is a deficient number, since it is larger than the sum of its proper divisors (2108371351).

14343204013241 is an equidigital number, since it uses as much as digits as its factorization.

14343204013241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2108371350.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 14343204013241 its reverse (14231040234341), we get a palindrome (28574244247582).

The spelling of 14343204013241 in words is "fourteen trillion, three hundred forty-three billion, two hundred four million, thirteen thousand, two hundred forty-one".