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14343330545 = 529808112241
BaseRepresentation
bin11010101101110110…
…11101101011110001
31101000121111200112122
431112323131223301
5213333343034140
610331135204025
71015304204135
oct152673355361
941017450478
1014343330545
1160a0488595
122943676615
13147779b44b
149a0d293c5
1558e350ab5
hex356eddaf1

14343330545 has 16 divisors (see below), whose sum is σ = 17809171920. Its totient is φ = 11076710400.

The previous prime is 14343330479. The next prime is 14343330619. The reversal of 14343330545 is 54503334341.

It can be written as a sum of positive squares in 8 ways, for example, as 1000077376 + 13343253169 = 31624^2 + 115513^2 .

It is not a de Polignac number, because 14343330545 - 212 = 14343326449 is a prime.

It is a super-4 number, since 4×143433305454 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1165625 + ... + 1177865.

It is an arithmetic number, because the mean of its divisors is an integer number (1113073245).

Almost surely, 214343330545 is an apocalyptic number.

It is an amenable number.

14343330545 is a deficient number, since it is larger than the sum of its proper divisors (3465841375).

14343330545 is a wasteful number, since it uses less digits than its factorization.

14343330545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20356.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 14343330545 its reverse (54503334341), we get a palindrome (68846664886).

The spelling of 14343330545 in words is "fourteen billion, three hundred forty-three million, three hundred thirty thousand, five hundred forty-five".

Divisors: 1 5 29 145 8081 12241 40405 61205 234349 354989 1171745 1774945 98919521 494597605 2868666109 14343330545