Base | Representation |
---|---|
bin | 1000010110010101010… |
… | …1110011001011000011 |
3 | 111201020011121222021011 |
4 | 2011211111303023003 |
5 | 4322223114243321 |
6 | 145520455141351 |
7 | 13235301011254 |
oct | 2054525631303 |
9 | 451204558234 |
10 | 143434134211 |
11 | 55914913a95 |
12 | 2396b974857 |
13 | 106ab1a9784 |
14 | 6d29762b2b |
15 | 3ae746cae1 |
hex | 21655732c3 |
143434134211 has 2 divisors, whose sum is σ = 143434134212. Its totient is φ = 143434134210.
The previous prime is 143434134167. The next prime is 143434134227. The reversal of 143434134211 is 112431434341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143434134211 - 29 = 143434133699 is a prime.
It is not a weakly prime, because it can be changed into another prime (143434104211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71717067105 + 71717067106.
It is an arithmetic number, because the mean of its divisors is an integer number (71717067106).
Almost surely, 2143434134211 is an apocalyptic number.
143434134211 is a deficient number, since it is larger than the sum of its proper divisors (1).
143434134211 is an equidigital number, since it uses as much as digits as its factorization.
143434134211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13824, while the sum is 31.
Adding to 143434134211 its reverse (112431434341), we get a palindrome (255865568552).
The spelling of 143434134211 in words is "one hundred forty-three billion, four hundred thirty-four million, one hundred thirty-four thousand, two hundred eleven".
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