Base | Representation |
---|---|
bin | 1101000010111100000100… |
… | …0010010110011101011001 |
3 | 1212210021201101112211110101 |
4 | 3100233001002112131121 |
5 | 3340003241402422223 |
6 | 50301334314015401 |
7 | 3010221010561315 |
oct | 320570102263531 |
9 | 55707641484411 |
10 | 14344134420313 |
11 | 4630349a25115 |
12 | 1737ba5717561 |
13 | 80085255c259 |
14 | 37838ccc2b45 |
15 | 19d1cd01c4ad |
hex | d0bc1096759 |
14344134420313 has 4 divisors (see below), whose sum is σ = 14378368631760. Its totient is φ = 14309900208868.
The previous prime is 14344134420299. The next prime is 14344134420359. The reversal of 14344134420313 is 31302443144341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14344134420313 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14344134426313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17117105095 + ... + 17117105932.
It is an arithmetic number, because the mean of its divisors is an integer number (3594592157940).
Almost surely, 214344134420313 is an apocalyptic number.
It is an amenable number.
14344134420313 is a deficient number, since it is larger than the sum of its proper divisors (34234211447).
14344134420313 is an equidigital number, since it uses as much as digits as its factorization.
14344134420313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34234211446.
The product of its (nonzero) digits is 165888, while the sum is 37.
Adding to 14344134420313 its reverse (31302443144341), we get a palindrome (45646577564654).
The spelling of 14344134420313 in words is "fourteen trillion, three hundred forty-four billion, one hundred thirty-four million, four hundred twenty thousand, three hundred thirteen".
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