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14344400311233 = 336131323406247
BaseRepresentation
bin1101000010111101000011…
…1000101001001111000001
31212210022101220212111020020
43100233100320221033001
53340004312434424413
650301420533004053
73010230416606436
oct320572070511701
955708356774206
1014344400311233
114630476021983
12173805a783629
13800895676965
143783b6337b8d
1519d1e653ec23
hexd0bd0e293c1

14344400311233 has 8 divisors (see below), whose sum is σ = 19131160721088. Its totient is φ = 9560286721104.

The previous prime is 14344400311231. The next prime is 14344400311253. The reversal of 14344400311233 is 33211300444341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14344400311233 - 21 = 14344400311231 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14344400311194 and 14344400311203.

It is not an unprimeable number, because it can be changed into a prime (14344400311231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 661692285 + ... + 661713962.

It is an arithmetic number, because the mean of its divisors is an integer number (2391395090136).

Almost surely, 214344400311233 is an apocalyptic number.

It is an amenable number.

14344400311233 is a deficient number, since it is larger than the sum of its proper divisors (4786760409855).

14344400311233 is a wasteful number, since it uses less digits than its factorization.

14344400311233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1323409863.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 14344400311233 its reverse (33211300444341), we get a palindrome (47555700755574).

The spelling of 14344400311233 in words is "fourteen trillion, three hundred forty-four billion, four hundred million, three hundred eleven thousand, two hundred thirty-three".

Divisors: 1 3 3613 10839 1323406247 3970218741 4781466770411 14344400311233