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14345000281 is a prime number
BaseRepresentation
bin11010101110000011…
…10101010101011001
31101000201122111222201
431113001311111121
5213334310002111
610331235050201
71015324330153
oct152701652531
941021574881
1014345000281
1160a1419037
122944140961
131477c34461
149a1241ad3
1558e5806c1
hex357075559

14345000281 has 2 divisors, whose sum is σ = 14345000282. Its totient is φ = 14345000280.

The previous prime is 14345000221. The next prime is 14345000291. The reversal of 14345000281 is 18200054341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14314926025 + 30074256 = 119645^2 + 5484^2 .

It is a cyclic number.

It is not a de Polignac number, because 14345000281 - 221 = 14342903129 is a prime.

It is a super-2 number, since 2×143450002812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14345000221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172500140 + 7172500141.

It is an arithmetic number, because the mean of its divisors is an integer number (7172500141).

Almost surely, 214345000281 is an apocalyptic number.

It is an amenable number.

14345000281 is a deficient number, since it is larger than the sum of its proper divisors (1).

14345000281 is an equidigital number, since it uses as much as digits as its factorization.

14345000281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 28.

The spelling of 14345000281 in words is "fourteen billion, three hundred forty-five million, two hundred eighty-one", and thus it is an aban number.