Base | Representation |
---|---|
bin | 1101000011000000011111… |
… | …0001100111011000010011 |
3 | 1212210101210002201021101221 |
4 | 3100300013301213120103 |
5 | 3340013204212344012 |
6 | 50302052151105511 |
7 | 3010262301301522 |
oct | 320600761473023 |
9 | 55711702637357 |
10 | 14345321215507 |
11 | 46308a8931997 |
12 | 1738277072297 |
13 | 8009b13ac229 |
14 | 3784627764b9 |
15 | 19d24c2ea507 |
hex | d0c07c67613 |
14345321215507 has 2 divisors, whose sum is σ = 14345321215508. Its totient is φ = 14345321215506.
The previous prime is 14345321215483. The next prime is 14345321215549. The reversal of 14345321215507 is 70551212354341.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14345321215507 is a prime.
It is not a weakly prime, because it can be changed into another prime (14345321215567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172660607753 + 7172660607754.
It is an arithmetic number, because the mean of its divisors is an integer number (7172660607754).
Almost surely, 214345321215507 is an apocalyptic number.
14345321215507 is a deficient number, since it is larger than the sum of its proper divisors (1).
14345321215507 is an equidigital number, since it uses as much as digits as its factorization.
14345321215507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504000, while the sum is 43.
Adding to 14345321215507 its reverse (70551212354341), we get a palindrome (84896533569848).
The spelling of 14345321215507 in words is "fourteen trillion, three hundred forty-five billion, three hundred twenty-one million, two hundred fifteen thousand, five hundred seven".
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