Base | Representation |
---|---|
bin | 11010101110111001… |
… | …01000001100000001 |
3 | 1101001012212101011100 |
4 | 31113130220030001 |
5 | 213343104234241 |
6 | 10332045405013 |
7 | 1015441123335 |
oct | 152734501401 |
9 | 41035771140 |
10 | 14352024321 |
11 | 60a5386328 |
12 | 2946569769 |
13 | 14795235ab |
14 | 9a214d7c5 |
15 | 58eebb9b6 |
hex | 357728301 |
14352024321 has 12 divisors (see below), whose sum is σ = 20786284948. Its totient is φ = 9542362464.
The previous prime is 14352024289. The next prime is 14352024331. The reversal of 14352024321 is 12342025341.
14352024321 is a `hidden beast` number, since 1 + 435 + 202 + 4 + 3 + 21 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 11693178225 + 2658846096 = 108135^2 + 51564^2 .
It is not a de Polignac number, because 14352024321 - 25 = 14352024289 is a prime.
It is a super-2 number, since 2×143520243212 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14352024331) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2134270 + ... + 2140983.
Almost surely, 214352024321 is an apocalyptic number.
It is an amenable number.
14352024321 is a deficient number, since it is larger than the sum of its proper divisors (6434260627).
14352024321 is a wasteful number, since it uses less digits than its factorization.
14352024321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4275632 (or 4275629 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 14352024321 its reverse (12342025341), we get a palindrome (26694049662).
The spelling of 14352024321 in words is "fourteen billion, three hundred fifty-two million, twenty-four thousand, three hundred twenty-one".
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